In this puzzle, we’re going learn to about SQL set operators. Set operators allow us to compare rows from two or more tables to arrive at a result. For several classes of problems, is is much easier to use a set operation, than join data.
Solving puzzles is a great way to learn SQL. Nothing beats practicing what you’ve learned. Once you have figured out the puzzle, post you answer in the comments so we all can learn from one another.
Table of contents
SQL Set Operators Puzzle – Part I
Given two lists of numbers: A and B
- Select all odd numbers ordered from highest to lowest
- Select all numbers from A that aren’t in B
- Select All numbers common to A and B
*** Don’t use joins or subqueries to answer these questions.
Understanding Set Operators versus Joins
Before we get into the answers I think it is important for you to know the difference between a join and set operation.
Though both concepts are used to combine data from multiple tables, join combine columns from separate tables; whereas, set operations combine rows from separate tables.
For instance, union is used to combine rows from two or more table in to a single result. It is difficult to do this using JOIN.
We are going to use the SQL set operators UNION, INTERSECT, and EXCEPT to answer today’s question. Below is a visual summary of these operations:
Let’s answer the first question:
Answer #1: Select all odd numbers ordered from highest to lowest
To do this we’ll combine the results of two queries, one from table A the other from B. In both case, we want only odd numbers. These are numbers, that when divided by 2, have a remainder of one.
Once we have a combined set, we’ll order the results.
Here are the tools we’ll need to use:
- % – This is the modulus operator. Well use to to get the remainder when we divide number by 2. Numbers with a remainder of 1 are odd.
- UNION – This set operator allows us to combine rows from one result set with another if each result has the same number of columns and datatypes.
- ORDER BY DESC – We use the ORDER BY clause to sort values.
The query to get odd number from table A is
SELECT Number FROM @A WHERE Number % 2 = 1
The modulo operator (%) may seem strange, but is it really handy!
We repeat the same query for table B and combine them using UNION ALL and ORDER the results.
SELECT Number FROM @A WHERE Number % 2 = 1 UNION ALL SELECT Number FROM @B WHERE Number % 2 = 1 ORDER BY Number DESC
Notice that I used UNION ALL. This returns every row for the union-ed results, even duplicate values. The above query returns 20 rows, below are some of the results:
If I ran the query without ALL, then only 15 rows are returned; try it!
If you want to learn more about the UNION operator, I would recommend this article on UNIONS.
Answer#2: Select all numbers From A that aren’t in B
To answer this question we’ll use the EXCEPT operator. It will limit our result to only those rows that are exclusive to one table.
For our purposes, think of table A as the orange table, and B as the blue. When we do A EXCEPT B, we are going return the orange crescent. This represents rows exclusive to A.
Here is the query to do so:
SELECT Number FROM @A EXCEPT SELECT Number FROM @B
In this example, we retrieve all rows from A, they are then compared to all rows from B, and only those rows found in A, but Not B are returned in the result:
I’m sure some of you were thinking of other solutions, such as those that use a JOIN or Subquery.
Here is the solution as a subquery:
SELECT Number FROM @A WHERE Number NOT IN (SELECT Number FROM @B)
I show you this, so you can understand that there are many ways to solve the same problem!
Answer#3: Select All Numbers Common to A and B
To find all numbers common between two results we can use the INTERSECT operator. These are the numbers which “overlap” in our diagram.
Though this was the last question in the puzzle, I think it is the easiest to answer!
SELECT Number FROM @A INTERSECT SELECT Number FROM @B
Can you think of another way of showing numbers common to both tables? What about an INNER JOIN?
Here is another way to get the same result:
SELECT A.Number FROM @A A INNER JOIN @B B ON A.Number = B.Number
So how did you answer the puzzle questions? I would really like to know. Put your answers in the comments!
Also, if you have any ideas for more puzzles, let me know.